We describe an algorithm that finds a minimum cost schedule, including spill code, for a register-constrained machine that can issue up to one arithmetic operation and one memory access operation at a time, under the restrictions that the dependence graph is a full binary tree, all arithmetic and store operations have unit latency, and all load operations have a latency of 1 or all load operations have a latency of 2. This problem is a generalization of two problems whose efficient solutions are well understood: optimaldual-issue scheduling without spills for binary expression trees, solved by Bernstein, Jaffe, and Rodeh [SIAM J. Comput., 18 (1989), pp. 1098--1127], and optimal single-issue scheduling with spill code and delayed loads, solved by Kurlander, Proebsting, and Fischer [ ACM Transactions on Programming Languages and Systems, 17 (1995), pp. 740--776], both assuming a fixed number of registers. We show that the algorithm's complexity is O(nk) where n is the number of operations to be scheduled and k is the number of spills in the schedule. The cost of a "contiguous" schedule (i.e., its length) is shown to be $\rho + 2k + g + |A|$, where $\rho$ is the number of registers used, |A| is the number of arithmetic operations, k is the number of spills, and g is the number of empty slots in the associated single processor schedule. Therefore all contiguous schedules formed from optimal single processor schedules have minimum cost.