The synthesis and crystal structure of two complexes resulting from interaction between NiBr 2 and triphenylarsine oxide (Ph 3AsO) is described. Green and orange complexes can be obtained from the blue, probably tetrahedral complex [NiBr 2(Ph 3AsO) 2], depending on the solvents used for recrystallization. NiBr 2·4[(C 6H 5) 3AsO]·8H 2O (green): M = 1650.2, P2 1/c, a = 13.731(2), b = 16.267(3), c = 17.647(2) Å, β = 112.04(1)°, V = 3651.4 Å 3, Z = 2, D x = 1.501 g cm -3, CuKα, λ = 1.54184 Å, μ = 38.67 cm -1, R = 0.039, 3741 unique reflections, 3203 with I > 3σ(I). NiBr 2·4[(C 6H 5) 3AsO]·3|2(C 6H 5CH 3)·H 2O (orange): M = 1663.7, P 1 , a = 12.647(8), b = 13.953(5), c = 22.853(6) Å, α = 90.91(3), β = 96.70(4), γ = 111.16(4)°, V = 3727.4 Å 3, Z = 2, D x = 1.482 g cm -3, MoKα, λ = 0.71073 Å, μ = 30.48 cm -1, R = 0.087, 8600 unique reflections, 4293 with I > 3σ(I). In the green complex the Ni(II) ion is sited on a center of symmetry and is octahedrally coordinated to six water molecules, hydrogen bonded to the Ph 3AsO molecules and to the bromide anions forming a second coordination sphere in a nearly octahedral arrangement. In the orange complex the cation is pentacoordinated with the four oxygen atoms of the Ph 3AsO ligands forming the basis of a tetragonal pyramid and with one Br - anion in the apical position. The absorption spectrum of the orange complex is compared with the spectra of other Ni(II) square pyramidal complexes described in the literature.
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