Abstract

Pure CFTs have vanishing β-function at any value of the coupling. One example of a pure CFT is the O(N) Wess-Zumino model in 2+1 dimensions in the large N limit. This model can be analytically solved at finite temperature for any value of the coupling, and we find that its entropy density at strong coupling is exactly equal to frac{31}{35} of the non-interacting Stefan-Boltzmann result. We show that a large class of theories with equal numbers of N-component fermions and bosons, supersymmetric or not, for a large class of interactions, exhibit the same universal ratio. For unequal numbers of fermions and bosons we find that the strong-weak thermodynamic ratio is bounded to lie in between frac{4}{5} and 1.

Highlights

  • This model can be analytically solved at finite temperature for any value of the coupling, and we find that its entropy density at strong coupling is exactly equal to

  • For unequal numbers of fermions and bosons we find that the strong-weak thermodynamic ratio is bounded to lie in between

  • It is straightforward to show that these divergences are suppressed by 1/N, such that in the large N limit, the theory has vanishing β-function for all λ, which is a hallmark of pure CFTs

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Summary

Calculation

Let us consider the O(N) supersymmetric Wess-Zumino model [8] in 2+1 dimensions given by the superspace action. Introducing an auxiliary field σ = φcφc/N and its Lagrange multiplier ζ as 1 = DσDζei ζ(σ−φcφc/N), only the zero modes of σ, ζ contribute to the leading order large N result of the partition function. Where bosonic and fermionic sum-integrals in 3 − 2 dimensions are written as K =. Where the bosonic and fermionic thermal sum-integrals JB, JF in 2+1 dimensions are finite in the → 0 limit. For large N, the partition function may be evaluated exactly using the saddle points located at iζ = z∗, σ = σ∗ given by the solution of the non-perturbative coupled gap equations z∗ 3σ2. It is straightforward to verify that in the weak coupling limit λ → 0, the solution to these equations is mF = mB = 0, indicating vanishing thermal masses for both bosons and fermions. Bosons and fermions develop non-vanishing thermal masses.

Thermodynamics
Strong coupling universality
Changing the balance between fermions and bosons
Summary and conclusions
Full Text
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