Abstract

The reactions between trans-[Au(CN) 2 X 2 ] - (X = Cl or Br) and Me 2 S have been studied by conventional and high-pressure stopped-flow spectrophotometry in acidic aqueous solution containing 10% (w/w) methanol. The overall stoichiometry Au III ∶Me 2 S is 1∶(1.0 ± 0.1) in agreement with the reaction: trans-[Au(CN) 2 X 2 ] - + Me 2 S + H 2 O → [Au(CN) 2 ] - + Me 2 SO + 2H + + 2X - . Initial rapid substitution processes result in the formation of a pre-equilibrium between transient gold(III) complexes, which are reduced to [Au(CN) 2 ] - in a subsequent slower redox process. Complexes trans-[Au(CN) 2 X(Me 2 S)] with an asymmetric electron distribution along the X–Au–S axis are reduced rapidly via an intermolecular process, in which Me 2 S attacks a co-ordinated halide. The complex trans-[Au(CN) 2 (Me 2 S) 2 ] , on the other hand, undergoes slow reduction to gold(I) involving a water molecule. The rapid halide-mediated oxidation of thioethers implies that reduction of metal ions in biological systems by such moieties should be favoured in extracellular environments, where the chloride concentrations are high.

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