Reaction of lithium tetrahydroaluminate with hexafluorobenzene yields pentafluorobenzene. Pentafluorobenzene reacts further with LiAlH4 to give 1,2,4,5-tetrafluorobenzene. The products are formed by a combination of (i) reduction (hydride for fluoride replacement) of the fluoroaromatic compound, and (ii) hydrolysis of one of the compounds LiAl(C6F4H)H2F or LiAl(C6F5)H2F that are formed in the reactions. These competing reactions take place to a similar extent and are much faster in tetrahydrofuran than in diethyl ether. ��� In tetrahydrofuran, 1,2,4,5-tetrafluorobenzene is metalated by LiAlH4. The compounds LiAl(C6F4H)H3, LiAl(C6F4H)2H2, and LiAl(C6F4H)3H are proposed as products of the reaction. ��� The fluorocarbon-aluminium compounds have been characterized by quantitative determination of the products of hydrolysis and by 1H and 19F N.M.R. spectroscopy.