AbstractA series of benzo‐ 1,3,3‐diphosphaborolanes C6H4(PR)2BR' (R = H, iPr, SiMe3; R' = R2N, R) has been prepared by several routes and characterized by spectroscopic and – in part – by X‐ray diffraction methods. They feature pyramidal P atoms with the substituents in antiperiplanar positions. The P atoms act as coordination sites for the (CO)5Cr fragment. In contrast to the R2N‐bearing benzo‐1,3,2‐diphosphaborolanes, the derivative C6H4(PH)2BCMe3 (4f) dimerizes by additional B–P bond formation to produce a pentacyclic system (4f)2. – The reaction of C6H4(PHNa)2 with B2(NMe2)2Cl2 in THF/hexane yields the acyclic phosphanylborane Me2NB(PH–C6H4PH2)2 (15). However, if C6H4[P(iPr)Li]2 is allowed to react with B2(NMe2)2Cl2, the benzo‐1,4,2,3‐diphosphadiborinane 13 is obtained, together with its rearrangement product 2‐bis(dimethylamino)borylbenzo‐1,3,2‐diphosphaborolane 14 which dimerizes to (14)2. — In contrast, the almost planar ring of the 2,3‐dimesitylbenzo‐1,4,2,3‐diphosphadiborinane (16) possesses P and B atoms with a planar geometry. Short B–B and B–P bonds suggest that this new heterocycle can be regarded as a 6π electron system. Moreover, the benzo‐1,5,2,3,4‐diphosphatriborepane 18 forms readily forms readily from C6H4(PHNa)2 and Br(Me2N)B–B(N‐Me2)–B(NMe2) Br to give a tub‐shaped seven‐membered C2B3P2 ring system with the P atoms in a pyramidal and the B atoms in a planar environment.