Deuterons are bosons and as such, under proper conditions, will Bose condense. A configuration which permits this phenomenon is described in which deuterons are weakly bound at interstitial sites of the metal palladium. It is argued that at a moderate value of the deuterium-to-palladium concentration ratio, a magnetically driven current in a single-crystal loop of this material will become “class B” superconducting at the critical temperature, T c, where “class B” denotes heavy-boson charge flow. Two distinct regimes are examined in which the deuteron kinetic energy, E, is large or small compared to the activation energy, E a. In the domain E< E a, stemming from the London criterion for Bose-condensation and the tunneling matrix element, an expression for T c is obtained which, for deuteron propagation in palladium, is noted to be infinitesimally small, rendering the proposed phenomenon unfeasible. In the domain E > E a, first-order estimates of the nearly-free-particle model, together with the London criterion, give the critical value T c≈9.1 K. It is shown that the condition E > E a may be established for sufficiently short rise time of an imposed magnetic field. A calculation is included which indicates that at these low temperatures, phonon effects in the present model are minimal. Metallurgical limitations on obtaining a single-crystal loop of palladium, with the fcc structure continuously maintained, imply the condition ϱ≳1.75 × 10 3 b, where ϱ is the radius of curvature of the palladium current loop and b is its diameter.
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