In this paper, we examine a class of doubly resolvable combinatorial objects. Let $$t, k, \lambda , s$$t,k,ź,s and v be nonnegative integers, and let X be a set of v symbols. A generalized Howell design, denoted t-$$\mathrm {GHD}_{k}(s,v;\lambda )$$GHDk(s,vźź), is an $$s\times s$$s×s array, each cell of which is either empty or contains a k-set of symbols from X, called a block, such that: (i) each symbol appears exactly once in each row and in each column (i.e. each row and column is a resolution of X); (ii) no t-subset of elements from X appears in more than $$\lambda $$ź cells. Particular instances of the parameters correspond to Howell designs, doubly resolvable balanced incomplete block designs (including Kirkman squares), doubly resolvable nearly Kirkman triple systems, and simple orthogonal multi-arrays (which themselves generalize mutually orthogonal Latin squares). Generalized Howell designs also have connections with permutation arrays and multiply constant-weight codes. In this paper, we concentrate on the case that $$t=2$$t=2, $$k=3$$k=3 and $$\lambda =1$$ź=1, and write $$\mathrm {GHD}(s,v)$$GHD(s,v). In this case, the number of empty cells in each row and column falls between 0 and $$(s-1)/3$$(s-1)/3. Previous work has considered the existence of GHDs on either end of the spectrum, with at most 1 or at least $$(s-2)/3$$(s-2)/3 empty cells in each row or column. In the case of one empty cell, we correct some results of Wang and Du, and show that there exists a $$\mathrm {GHD}(n+1,3n)$$GHD(n+1,3n) if and only if $$n \ge 6$$nź6, except possibly for $$n=6$$n=6. In the case of two empty cells, we show that there exists a $$\mathrm {GHD}(n+2,3n)$$GHD(n+2,3n) if and only if $$n \ge 6$$nź6. Noting that the proportion of cells in a given row or column of a $$\mathrm {GHD}(s,v)$$GHD(s,v) which are empty falls in the interval [0, 1 / 3), we prove that for any $$\pi \in [0,5/18]$$źź[0,5/18], there is a $$\mathrm {GHD}(s,v)$$GHD(s,v) whose proportion of empty cells in a row or column is arbitrarily close to $$\pi $$ź.