The radical intermediates formed initially in the reaction of S 2O 6F 2 with S 4N 4 and S 8 have been studied by ESR spectroscopy at X-band level. The transient radical formed in the reaction between S 2O 6F 2 and S 4N 4 has the spin Hamiltonian parameters g xx =2.0014, g yy =2.0054, g zz =2.0249, A xx =22.5 MHz, A yy =4.5 MHz, A zz =2.0 MHz and Q zz =4 MHz as determined by simulation of ESR lineshapes obtained from polycrystalline samples. The spin Hamiltonian parameters are very similar to those previously reported for [S 3N 2] +·, and the spectra are interpreted as being most likely due to the [S 3N 2] +· radical. The reaction between S 2O 6F 2 and S 8 under similar conditions produces a radical that has a g-tensor of the form g xx =2.0026, g yy =2.0184, g zz =2.0258, as determined by simulation. The transient species generated is postulated to be a similar S 5 +· radical.
Read full abstract