AbstractThe reaction of 4‐hydrazino‐7‐phenylpyrazolo[1,5‐a]‐1,3,5‐triazine (4) with nitrous acid gave 8‐phenyltetrazolo[1,5‐e]pyrazolo[1,5‐a]‐1,3,5‐triazine (5b), which was determined by pmr and ir spectra to be in equilibrium with 4‐azido‐7‐phenylpyrazolo[1,5‐a]‐1,3,5‐triazine (5a). The equilibrium between the tetrazolo (5b) and azido (5a) forms was studied by pmr and an attempt was made to determine if substituents in the pyrazole nucleus could sufficiently stabilize the tricyclic tetrazolo form (5b) over the bicyclic azido form (5a). Thermal degradation of 5(a ⇌ b) in an aprotic solvent gave 4‐amino‐7‐phenylpyrazolo[1,5‐a]‐1,3,5‐triazine (7), indicating the probability of a nitrene mechanism involved in the decomposition. Heating 5 in aqueous base gave both 7 and the “hydroxy” analog, 7‐phenylpyrazolo[1,5‐a]‐1,3,5‐triazin‐4(3H)one (6), further substantiating the existence of a nitrene intermediate with a competing nucleophilic displacement of the azido group by a hydroxyl group. Cyclization of 4 with diethoxymethylacetate (DEMA) gave 8‐phenyl‐s‐triazolo[4,3‐e]pyrazolo[1,5‐a]‐1,3,5‐triazine (8), which underwent thermal rearrangement to 8‐phenyl‐s‐triazolo[2,3‐e]pyrazolo[1,5‐a]‐1,3,5‐triazine (9). Acid catalyzed ring opening of 9 with formic acid gave 3‐N‐formamido‐5‐phenyl‐2(2‐s‐triazolyl)pyrazole (10). The failure of 10 to recyclize to 9 with the resultant loss of water, supported the theory that the rearrangement of 8 to 9 might occur simply as a concerted, thermally induced “anhydrous” rearrangement rather than via a covalently hydrated intermediate or a Dimroth type mechanism (in the base catalyzed rearrangement).