Abstract
Abstract A potent carcinogen, 4-hydroxyaminoquinoline 1-oxide, was found to produce a stable free radical oxidatively. The structure of the free radical produced in dioxane was studied by analyizng the hyperfine structure of isotope-substituted 4-hydroxyaminoquinoline 1-oxides, and by comparing the values of the spin densities obtained from the coupling constants with those calculated by the unrestricted SCF MO method. It was concluded that the free radical has the same molecular skeleton as the parent compound, but that it loses a hydrogen atom on the nitrogen atom of the NHOH group.
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