Abstract

We investigate the hole-doped antiferromagnetic state in a two-orbital model of cuprates. The model also includes orbital. Unlike the one-orbital model, we find the antiferromagnetic state stable against the hole doping for the cuprates with orbital splitting between and orbitals being ∼1 eV. This results from the fact that the Hund’s coupling enforces the filling of orbital ≈1 indicated by a significant reduction of spectral density at the Fermi level. This, in turn, leads to the suppression of intraband fluctuations detrimental to the antiferromagnetic phase. In this scenario, hole doping involves removal of mainly electrons that are comparatively more localized. One important caveat of our meanfield theoretic result and conclusion is that they are reliable only for a very low hole doping region.

Highlights

  • After more than thirty years of discovery of cuprates exhibiting high-Tc superconductivity [1], several aspects of their behavior could not be understood within the one-orbital Hubbard model

  • We investigate the hole-doped antiferromagnetic state in a two-orbital model of cuprates

  • Unlike the one-orbital model, we find the antiferromagnetic state stable against the hole doping for the cuprates with orbital splitting between dx2−y2 and d3z2−r2 orbitals being ∼1 eV

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Summary

Introduction

After more than thirty years of discovery of cuprates exhibiting high-Tc superconductivity [1], several aspects of their behavior could not be understood within the one-orbital Hubbard model. Abstract We investigate the hole-doped antiferromagnetic state in a two-orbital model of cuprates. Unlike the one-orbital model, we find the antiferromagnetic state stable against the hole doping for the cuprates with orbital splitting between dx2−y2 and d3z2−r2 orbitals being ∼1 eV.

Results
Conclusion

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