Abstract

The crystal structure and superconductivity of another superconducting phase in the Tl-Ba-Ca-Cu-O system have been studied. This superconducting phase has a zero-resistance temperature of 100.6 K and diamagnetic susceptibility appears at 98.4 K. The ideal chemical formula is Tl2Ba2CaCu2O8. The crystal structure of this compound was determined by means of X-ray powder diffraction. It belongs to the body-centred tetragonal system with lattice constants a=3.847 AA and c=29.43 AA. Its space group is D4h17 (I4/mmm). Each unit cell contains two formula units. 2 Ca2+ cations occupy 2(a) equivalent point positions. 4 Ba2+, 4 Tl3+ and 4 Cu2+ cations occupy the same equivalent point positions 4(e) with respective atomic parameters z=0.115, 0.285 and 0.450. 16 O anions occupy 8(g) (z=0.450) and two 4(e) equivalent point positions (z=0.200 and 0.380). The crystal structure of Tl2Ba2CaCu2O8 is isomorphic with that of Bi2Sr2CaCu2O8. Comparing it with the structure of Tl2Ba2-xCa1+xCu3O9, both of them have the same lattice constant a, but they have different lattice constants c, as the stacking numbers along the c axis are different. The superconducting transition temperature of Tl2Ba2CaCu2O8 is lower than that of Tl2Ba2-xCa1+xCu3O9. The transition temperature Tc is possibly related to the magnitude of c and the Cu2+ content in the unit cell.

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