Abstract
The crystal structure of SnBr[N(SiMe3)2]3 has been determined from three-dimensional X-ray diffraction data collected by counter methods. This compound crystallizes in the rhombohedral space groupR3c witha=11.970(3) A, α=99.06(3)°, andZ=2forD c> =1.37 g cm−3. The finalR value was 0.027 based on 608 independent observed reflections. The molecule lies on a crystallographic three-fold axis which contains the Sn and Br atoms. The bromine atom is covalently coordinated to the tin atom at a Sn-Br separation of 2.519(2) A. The three nitrogen atoms complete the bonding to tin with an Sn-N bond length of 2.056(7) A.
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