Abstract

Treatment of Au 2(Ph 2PCH 2CH 2PPh 2)Cl 2 with one equivalent of the [Ru 5C(CO) 14] 2− dianion in the presence of TlPF 6 gives Ru 5C(CO) 14Au 2(Ph 2PCH 2CH 2PPh 2) ( 1) in good yield and the [{Ru 5C(CO) 14} 2Au 2(Ph 2PCH 2CH 2PPh 2)] 2− ( 2) anion in low yield. Complex 2 becomes the major product if 2 equivalents of [Ru 5C(CO) 14] 2− are used. Reaction of [Au 2(Ph 2PCH 2CH 2PPh 2)Cl 2] with 3 equivalents of [H 3Os 4(CO) 12] − anion in the presence of TlPF 6 affords {H 3Os 4(CO) 12} 2Au 2(Ph 2PCH 2CH 2PPh 2) ( 3) in reasonable yield. X-ray diffraction studies of 1 and 3 show that they contain the [Au 2(Ph 2PCH 2CH 2PPh 2)] 2+ fragment in different coordination modes.

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