Abstract

For a natural number k≥ 2 letρ=ρ(k) be the smallest natural number which does not dividek− 1. We show that for any subset A of a right cancellative semigroup S which contains no solutions of the equation x1+⋯ +xk=y there is an element s inS such that the setsA, A+s, . ,A + (ρ− 1)sare pairwise disjoint. In particular, if S is finite, such a set A has at most | S |/ρ elements. This estimate is sharp.

Talk to us

Join us for a 30 min session where you can share your feedback and ask us any queries you have

Schedule a call

Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.