Abstract
Sodium or magnesium amalgam reductions of tetrahydrofuran solutions of [MH(PEt3)3][BPh4](M = Pt or Pd), or of toluene solutions of [PtH(Cl)(PEt3)2] in the presence of an excess of PEt3, produce hydrogen and [Pt(PEt3)3] or Pd metal. The mechanism of the reaction is discussed and [Ru(bipy)3]2+*(bipy = 2,2′-bipyridyl) is shown not to reduce [PdH(PEt3)3]+ in aqueous solution. The compound [Pd(PEt3)3] dissolves in buffered or acidic water to produce [PdH(PEt3)3]+ although it is less nucleophilic than [Pt(PEt3)3]. In the presence of chloride ion at low pH, [PdH(Cl)(PEt3)2] is formed in high yield.
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