Abstract
An equation of crack channel propagation is derived under the assumption that the crack opening is a slow process. The equation contains only one phenomenological parameter: time τ of melt free flow in a crack channel (free flow means that the hydrodynamic drag is absent). Time τ is found to be about 10 s. A solution to this equation is checked as applied to the Great Tolbachin Fissure Eruption, which occurred in 1975–1976. Satisfactory agreement between calculated and observed data for the magma eruption rate (V = 0.15 m/s) and crack opening time (T = 8.4 days) is obtained.
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