Abstract

This paper deals with the existence of positive solutions of nonlinear differential equation $$\begin{aligned} u^{\prime \prime }(t)+ a(t) f(u(t) )=0,\quad 0<t <1, \end{aligned}$$ subject to the boundary conditions $$\begin{aligned} u(0)=\sum _{i=1}^{m-2} a_i u (\xi _i) ,\quad u^{\prime } (1) = \sum _{i=1}^{m-2} b_i u^{\prime } (\xi _i), \end{aligned}$$ where $$ \xi _i \in (0,1) $$ with $$ 0< \xi _1<\xi _2< \cdots<\xi _{m-2} < 1,$$ and $$a_i,b_i $$ satisfy $$a_i,b_i\in [0,\infty ),~~ 0< \sum _{i=1}^{m-2} a_i <1,$$ and $$ \sum _{i=1}^{m-2} b_i <1. $$ By using Schauder’s fixed point theorem, we show that it has at least one positive solution if f is nonnegative and continuous. Positive solutions of the above boundary value problem satisfy the Harnack inequality $$\begin{aligned} \displaystyle \inf _{0 \le t \le 1} u(t) \ge \gamma \Vert u\Vert _\infty . \end{aligned}$$

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