Abstract

The paper deals with the classical problem of minimizing the makespan in a three-machine flow shop. When any one of the three machines is a non-bottleneck machine, the problem is efficiently solvable by one of three algorithms from the literature. We show that even if one chooses the best solution, the worst-case performance ratio of these algorithms is 2, and the bound of 2 is tight. We also present a new sufficient condition for identifying the intermediate non-bottleneck machine which is weaker than all conditions proposed so far. Copyright © 2000 John Wiley & Sons, Ltd.

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