Abstract
The energy spectrum of the luminescence induced by positive muons stopped in KBr has been obtained. This spectrum shows a Gaussian line shape with the peak located at 2.82(2) eV [FWHM, 0.56(5) eV], which is shifted considerably from the 2.28-eV luminescence line due to the lowest triplet state of self-trapped excitons (STE's). This result, together with the temperature dependences of its lifetime and yield, strongly suggests that the initial state of the observed luminescence is a triplet STE state that is specific to the muon(ium)-KBr system.
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