Abstract
It is shown how to obtain metastable supersymmetry breaking vacua in a perturbative gauge theory without gauge singlets. An explicit SU(5) example provides a scenario where a grand unified symmetry and supersymmetry are broken by the same field. The minimal renormalizable example requires the use of two adjoints, but it inevitably leads to unwanted light states. Viable alternatives consist of allowing for non‐renormalizable operators, of employing four adjoints or of adding at least one field in a different representation.
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