Abstract

Let Xn be a finite CW complex with cohomology type (a, b), characterized by an integer n > 1 [20]. In this paper, we show that if G = (Z2)q acts freely on the product Y = Qmi=1 Xin, where Xin are finite CW complexes with cohomology type (a, b), a and b are even for every i, then q ? m. Moreover, for n even and a = b = 0, we prove that G = (Z2)q (q ? m) is the only finite group which can act freely on Y. These are generalizations of the results which says that the rank of a group acting freely on a space with cohomology type (a, b) where a and b are even, is one and for n even, G = Z2 is the only finite group which acts freely on spaces of cohomology type (0, 0) [17].

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