Abstract
AbstractIt follows from our analysis that the formation of the Kondo insulator (KI) state in CeRh1−xPdxSb is due to the formation of the collective Kondo singlet state. The semiconducting gap in CeRhSb is strongly reduced with Pd substitution, the activated behaviour in the resistivity is observed only for $x\; < \;0.08$. In this paper, we present a schematic phase diagram for CeRh1−xPdxSb on the temperature T−x plane, based on the magnetic susceptibility data and resistivity. For $x \leq 0.06$ the intra‐atomic hybridization energy V dominates the KI ground state. With increase in x the hybridization V is strongly reduced, which leads to metallic properties of CeRh1−xPdxSb.
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