Abstract
Let $f(z) = \sum \nolimits _{n = 1}^\infty {{a_n}{z^n}}$, and set $G(z) = f{({z^{ - p}})^{ - /1p}} = \sum \nolimits _{n = 0}^\infty {{g_{np - 1}}{z^{1 - np}}}$. This paper finds an explicit formula for ${g_{np - 1}}$ in terms of the ${a_n}$. Such a formula (apparently previously unknown) may be very useful in the theory of univalent functions.
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