Abstract
This chapter discusses the bending theory for shells of revolution under axisymmetric load. Because of symmetry, the component of load in the x direction must vanish, that is, X = 0, and that the shear stress resultants N φθ and N θφ must also vanish. Terms involving differentiation with respect to θ cannot exist because of symmetry. As there is no variation of Nθ in the x direction and as X is zero, equilibrium in the x direction is identically satisfied. As the applied load on the shell of revolution is axisymmetric, the displacement of the shell surface because of this load will be axisymmetrical.
Talk to us
Join us for a 30 min session where you can share your feedback and ask us any queries you have
Disclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.