Abstract

The ${T}_{z}$=-(3/2), A=4n+1 nuclide $^{61}\mathrm{Ge}$ has been produced via the $^{40}\mathrm{Ca}$${(}^{24}$Mg,3n) reaction and identified by its beta-delayed proton emission. A single proton group at 3.11\ifmmode\pm\else\textpm\fi{}0.03 MeV with ${t}_{1/2}$=40\ifmmode\pm\else\textpm\fi{}15 ms has been observed, corresponding to decay of the T=(3/2) isobaric analog state in $^{61}\mathrm{Ga}$ to the ground state of $^{60}\mathrm{Zn}$. Searches for the beta-delayed proton decay of the next member of this series, $^{65}\mathrm{Se}$, to be produced by the $^{40}\mathrm{Ca}$${(}^{28}$Si,3n) reaction, have proven unsuccessful.

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