Abstract
The ${\mathit{T}}_{\mathit{Z}}$=-3/2, A=4n+1 nuclide $^{65}\mathrm{Se}$ produced in the $^{40}\mathrm{Ca}$${(}^{28}$Si,3n) reaction has been observed via beta-delayed proton emission. A single proton group at 3.55\ifmmode\pm\else\textpm\fi{}0.03 MeV has been observed, corresponding to the decay of the T=3/3 isobaric analog state in $^{65}\mathrm{As}$ to the ground state of $^{64}\mathrm{Ge}$. Combining this measurement with a Coulomb displacement energy calculation yields a mass excess for $^{65}\mathrm{Se}$ of -33.41\ifmmode\pm\else\textpm\fi{}0.26 MeV.
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