A novel method is established to determine thiamazole by phosphorus molybdenum blue spectrophotometry. The experiment indicates that PO 4 3− reacts with Mo 7O 24 6− in 0.30 mol/L H 2SO 4 solution to form a product with phosphorus–molybdenum heteropoly acid ([H 2PMo 12O 40] −). Then [H 2PMo 12O 40] − is deoxidized to form phosphorus molybdenum blue (H 3PO 4·10MoO 3·Mo 2O 5) by thiamazole. The amount of thiamazole can be determined based on the absorbance of phosphorus molybdenum blue ( λ max = 710 nm). A good linear relationship is obtained between the absorbance and the concentration of thiamazole in the range of 0.035–70 μg/mL. The equation of the linear regression is A = 0.03384 + 0.00834 c (μg/mL), with a linear correlation coefficient of 0.9990. The apparent molar absorption coefficient is 1.0 × 10 3 L/(mol cm). The method has been successfully applied to the determination of thiamazole in pharmaceutical samples with satisfactory results, and recoveries are in the range of 99.6–100.6%.
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