Let 6 be a commutative Noetherian ring containing the rational numbers, T a family of derivations mapping 6 into itself, and f a T-differential 6ideal (i. e., DE C f for every D C T). Theorem 1 shows that the associated prime ideals of f are also T-differential and that f has an irredundant primary decomposition into T-differential primary ideals. Theorem 2 shows that in studying a differential (i. e., T-differential for maximal T) prime ideal p in a finitely generated extension =k [xr, , xn] of a base field k one can localize, i. e., that p is differential in J if and only if p 6p is differential in the local ring 6p. Already here one needs more than the Noetherian condition and the study becomes essentially one for rings of finitely generated type, i. e., quotient rings of finite extensions of a base field k (of characteristic 0). We describe the further results for the case that j = k[x] is a finite integral domain or, equivalently, is the ring of an irreducible affine variety V over k. Theorem 3 shows that the simple subvarieties of V yield nondifferential ideals . By a lemma of Zariski, if p 6p is not differential, then the completion 6p of 6p is of the form O [Em]], where u C p p and is analytically independent over E. We say that V is analytically a product at or along an irreducible subvariety 't if the completion of O., where p =c ('t), is of the form just mentioned. Intuitively we think of V as somewhat like a cylinder built on the section u 0 of V. Then a component of the singular locus of V could not very well yield a non-differential ideal in 6; and the facts correspond to this intuition: Theorems 4 and 5 give the proof. Theorem 12, Corollary shows that V is analytically a product along a subvariety St if and only if the ideal of ' in the ring of V is not differential. While this is in some ways a satisfactory criterion (for a prime ideal to be differential), we are further concerned with the question whether the condition