Abstract
In the title compound, C18H14Cl2O4, the mean planes of the methyl acrylate unit and the phenyl ring of the benzaldehyde are approximately orthogonal to each other, making a dihedral angle of 83.31 (6)°. The O atom of the aldehyde group is displaced significantly from the phenyl ring plane by 0.226 (2) Å. The methyl acrylate group adopts an E conformation. In the crystal, inversion dimers linked by pairs of C—H⋯O hydrogen bonds generate R 2 2(24) loops.
Highlights
In the title compound, C18H14Cl2O4, the mean planes of the methyl acrylate unit and the phenyl ring of the benzaldehyde are approximately orthogonal to each other, making a dihedral angle of 83.31 (6)
Head of the Department of Physics, for providing facilities in the department to carry out this work
The mean planes formed by the methyl acrylate unit and the phenyl ring (C1–C6) are almost orthogonal to each other, with a dihedral angle of 83.31 (6)°
Summary
008, India, bDepartment of Physics, RKM Vivekananda College (Autonomous), Chennai 600 004, India, and cDepartment of Organic Chemistry, University of Madras, Maraimalai Campus, Chennai 600 025, India
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