Abstract
Effects of two-ripplon processes of electrons on the surface of liquid 4He are examined theoretically. In the derivation of the electron-ripplon interaction, effects of the barrier potential due to bulk liquid 4He are removed exactly by the canonical transformation. The effective interaction Hamiltonian so derived is different from the one used earlier. Calculations of the momentum loss rate and the energy loss rate of warm electrons are performed based on this Hamiltonian, and the momentum and energy loss rates due to the two-ripplon process are smaller by approximately an order of 10 −5 than those due to the one-ripplon process. This is in contrast to the earlier calculations in which the energy loss rate was claimed to be governed by the two-ripplon process.
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