Abstract
The infinite system L1, L2, …, Lr, … of parallel channels is receiving traffic by a Poisson input. Each call enters at L1, proceeding, if L1 was occupied, along the line of channels until it arrives at an unoccupied channel. Palm has solved the case of identical exponential channels. In what follows we shall consider identical channels with an arbitrary service-time distribution.
Talk to us
Join us for a 30 min session where you can share your feedback and ask us any queries you have
Schedule a callDisclaimer: All third-party content on this website/platform is and will remain the property of their respective owners and is provided on "as is" basis without any warranties, express or implied. Use of third-party content does not indicate any affiliation, sponsorship with or endorsement by them. Any references to third-party content is to identify the corresponding services and shall be considered fair use under The CopyrightLaw.
