Abstract
Total vapor pressures of As2Se3 and As2Te3 were measured by the torsion-effusion method, and their temperature dependences were found to fit the following equations: As2Se3(s), log(p/kPa) = (12.20 ± 0.20) to (9170 ± 130)/(T/K) and As2Te3(s), log(p/kPa) = (10.45 ± 0.20) to (8185 ± 150)/(T/K). Considering the complex mode of vaporizing of As2Se3, the mean second-law enthalpy and entropy values associated to the sublimation of 1 mol of the vapor mixture at the mid-point temperature, ΔH°(587 K) = (175 ± 3) kJ·mol-1 and ΔS°(587 K) = (233 ± 4) J·K-1·mol-1, were calculated from the temperature dependence of its vapor pressure. As2Te3 dissociates upon sublimation yielding As4(g) and Te(s). Both As4(g) and Te2(g) are present in the vapor over Te-saturated As2Te3, where the Te2(g) partial pressures are considered equal to the vapor pressure of the pure element. On this basis, treating the pressure data by second- and third-law methods, the standard sublimation enthalpy associated to the sublimation reaction, As2Te3(s) = 0.5 As4(g) + 3 Te(s), ΔH°(298 K) = 81 ± 2 kJ·mol-1, was determined.
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