Abstract

Photolyase repairs UV-induced cyclobutane-pyrimidine dimers in DNA by photoinduced electron transfer. The enzyme isolated from Escherichia coli contains 5,10-methenyltetrahydrofolate, which functions as the light-harvesting chromophore, and fully reduced flavin adenine dinucleotide (FAD), which functions as the redox catalyst. During enzyme preparation, the flavin is oxidized to FADH0, which is catalytically inert. Illumination of the enzyme with 300- to 600-nm light converts the flavin to the fully reduced form in a reaction that involves photooxidation of an amino acid in the apoenzyme. The results of earlier optical studies had indicated that the redox-active amino acid in this photoactivation process was tryptophan. We have now used time-resolved electron paramagnetic resonance (EPR) spectroscopy to investigate the photoactivation reaction. Excitation of the flavin-radical-containing inactive enzyme produces a spin-polarized radical that we identify by 2H and 15N labeling as originating from a tryptophan residue, confirming the inferences from the optical work. These results and Trp-->Phe replacement by site-directed mutagenesis reveal that flavin radical photoreduction is achieved by electron abstraction from Trp-306 by the excited-state FADH0. Analysis of the hyperfine couplings and spin density distribution deduced from the isotopic-labeling results shows that the product of the light-driven redox chemistry is the Trp-306 cation radical. The results strongly suggest that the active form of photolyase contains FADH- and not FADH2.

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