Abstract

The [Au(C6H5)Cl3]– ion undergoes reversible solvolysis of the chloride trans to C6H5– in methanol solution. The kinetics of the approach to equilibrium on adding excess of LiCl have been followed by stopped-flow spectrophotometry at temperatures below 0 °C and the rate and equilibrium constants determined. In the absence of added Cl– the complex exists mainly as trans-[Au(C6H5)(MeOH)Cl2]. The kinetics of the replacement of MeOH by a variety of nucleophiles have been studied. The reactivity follows the sequence NO2– < Cl– < Br– < N3–≈ I– < NCS– < thiourea but the nucleophilic discrimination is considerably less than that observed in other gold(III) complexes. The reaction with iodide leads to reduction of the substrate and the formation of I3– but the rate-determining step is shown to be a nucleophilic substitution. The kinetics of the reaction [Au(C6H5)Cl3]–+ nu–→trans-[Au(C6H5)Cl2(nu)]x–+ Cl– have been followed in methanol solution by working in the presence of excess of LiCl. Neutral nucleophiles enter by the usual direct associative pathway, the nucleophilicity increasing along the sequence pyridine < Et2S < thiourea. Nucleophilic discrimination is low. Anionic reagents do not react directly with the anionic [Au(C6H5)Cl3]– complex but enter by displacing methanol from the solvento species. In this respect [Au(C6H5)Cl3]– resembles [Pt(L)Cl3]–, where L is a neutral ligand with a moderate or high σ-donor trans effect.

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