Abstract
We calculate the structure of H3(SL2(Q),Z[12]). Let H3(SL2(Q),Z)0 denote the kernel of the (split) surjective homomorphism H3(SL2(Q),Z)→K3ind(Q). Each prime number p determines an operator 〈p〉 on H3(SL2(Q),Z) with square the identity. We prove that H3(SL2(Q),Z[12])0 is the direct sum of the (−1)-eigenspaces of these operators. The (−1)-eigenspace of 〈p〉 is the scissors congruence group, over Z[12], of the field Fp, which is a cyclic group whose order is the odd part of p+1.
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