Abstract
The reactions 11B(p, 3He) 9Be and 11B(p, t) 9B have been studied at 45 MeV proton energy. New T = 1 2 states have been observed at 15.96±0.04 MeV in 9Be and at 15.29±0.04 MeV and 15.58±0.04 MeV in 9B; and in addition there is a possible state or states at ≈ 15.13 MeV in 9Be. The results were compared to DWBA calculations with (1p) shell wave functions and there is reasonable agreement for the ground states, lowest 5 2 − excited states and the lowest 3 2 − (T = 3 2 ) analogue states. Several candidates are proposed for a 3 2 − (T = 1 2 ) state near the analogue state. The results are discussed in terms of isospin mixing in the analogue states, prompted by previously observed deviations of their masses from the quadratic multiplet mass equation. All the experimental evidence indicates that isospin mixing of more than a few percent is extremely unlikely.
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