Abstract
The reaction of [Os 6(CO) 18] 1 with [(SPPh 2) 2NH] in the presence of Me 3NO produces a purple compound characterized spectroscopically and by X-ray crystallography, as [HOs 6(CO) 17(SPPh 2) 2N] 2. The structure shows the hexanuclear fragment to have suffered a geometrical rearrangement to give a metal framework that can be described as an edge-bridged tetrahedron with an additional terminal osmium atom bonded to one of the bridged metal atoms. The ligand acts as a bimetallic tetraconnective unit through both sulphur atoms between two non-bonded osmium atoms.
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