Abstract
We consider the gap between the cost of an optimal assignment in a complete bipartite graph with random edge weights, and the cost of an optimal traveling salesman tour in a complete directed graph with the same edge weights. Using an improved “patching” heuristic, we show that with high probability the gap is O((lnn)2/n), and that its expectation is Ω(1/n). One of the underpinnings of this result is that the largest edge weight in an optimal assignment has expectation Θ(lnn/n). A consequence of the small assignment-TSP gap is an eO( √ n)-time algorithm which, with high probability, exactly solves a random asymmetric traveling salesman instance. In addition to the assignment-TSP gap, we also consider the expected gap between the optimal and second-best assignments; it is at least Ω(1/n2) and at most O(lnn/n2).
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