The Nitrogen‐Assisted Triphenylphosphine Displacement of Thiazoline Ligand in Palladium(II) Complex: Crystal Structures of [Pd(PPh3)2(η1‐\documentclass{article}\pagestyle{empty}\begin{document}$ \left[{{\rm Pd}\left({{\rm PPh}_3 } \right)_2 \left({n^1 \bar - } \right)\left({{\rm Br}} \right)} \right] $\end{document})(Br)] and [Pd(PPh3)(Br)]2(μ,η2‐\documentclass{article}\pagestyle{empty}\begin{document}$ \left[{{\rm Pd}\left({{\rm PPh}_3 } \right)_2 \left({{\rm Br}} \right)\left({{\rm \mu },n^2 \bar - } \right)_2 } \right] $\end{document})2

Abstract

AbstractTreatment of Pd(PPh3)4 with 2‐bromothiazoline, Br\documentclass{article}\pagestyle{empty}\begin{document}$ {\rm Br}, $\end{document}, in dichloromethane at ‐20 °C causes an oxidative addition reaction to produce the palladium complex [Pd(PPh3)2(η1\documentclass{article}\pagestyle{empty}\begin{document}$ \left[{{\rm Pd}\left({{\rm PPh}_3 } \right)_2 \left({{\rm \eta }^1 - } \right)\left({{\rm Br}} \right)} \right]2 $\end{document})(Br)] 2 by substituting two triphenylphosphine ligands. In dichloromethane complex 2 at room temperature for 8 h, it undergoes displacement of the triphenylphosphine ligand to form the dipalladium complex [Pd(PPh3)Br]2(μ,η2\documentclass{article}\pagestyle{empty}\begin{document}$ \left [{{\rm Pd}\left({{\rm PPh}_3 } \right)_2 \left({{\rm Br}} \right)} \right]_2 \left({{\rm \mu },{\rm \eta }^2 - } \right)_2 3 $\end{document})2 3 in which the two thiazoline ligands coordinated through carbon to one metal center and bridged the other metal through nitrogen atom. Complexes 2 and 3 are characterized by X‐ray diffraction analyses.