The identity $7^{3n}+7^{3n+1}=(2\cdot 7^n)^3$ and its generalizations

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Starting with the identity $7^{3n}+7^{3n+1}=(2\cdot 7^n)^3$ and its sibling, we prove that for any positive integer $m$, the diophantine equation $x^n+x^{n+k}=z^m$ has infinitely many solutions in nonzero integers $x$, $z$, $n$ and $k$. We show that in case $k>1$ the solutions come from the Catalan's Conjecture. We also solve three similar diophantine equations.

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Objectives: Diophantine research focuses on various ways to tackle multi variable and multi-degree Diophantine problems. A Diophantine equation is a polynomial equation with only integer solutions. The objective of this manuscript is to find the solutions to Polynomial Diophantine equation . Methods: Diophantine equations may have finite, infinite, or no solutions in integers. There is no universal method for finding solutions to Diophantine equations. Different choice of solutions in integers is obtained through using linear transformations and employing the factorization method. Findings: Many distinct patterns of integer solutions are obtained. Novelty: The main thrust is to illustrate different ways of obtaining various choices of solutions in integers to second-degree equations with four variables . Different choice of solutions in integers is obtained through using linear transformations and employing the factorization method. Utilization of substitution strategy reduces the given equation to a ternary quadratic equation for which solutions can be found easily. Mathematics Subject Classification:11D09 Keywords: Homogeneous second degree with four variables, Solutions in integers, Factorization method, Linear transformation, Polynomial diophantine equation

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<p>Let f(n)=1 if n=1, 2^(2^(n-2)) if n \\in {2,3,4,5}, (2+2^(2^(n-4)))^(2^(n-4)) if n \\in {6,7,8,...}. We conjecture that if a system T \\subseteq {x_i+1=x_k, x_i \\cdot x_j=x_k: i,j,k \\in {1,...,n}} has only finitely many solutions in integers x_1,...,x_n, then each such solution (x_1,...,x_n) satisfies |x_1|,...,|x_n| \\leq f(n). We prove that the function f cannot be decreased and the conjecture implies that there is an algorithm which takes as input a Diophantine equation, returns an integer, and this integer is greater than the heights of integer (non-negative integer, positive integer, rational) solutions, if the solution set is finite. We show that the conjecture and Matiyasevich's conjecture on finite-fold Diophantine representations are jointly inconsistent.</p>

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In a remark on page 80 of his classical book 250 Problems in Elementary Number Theory, SierpiƄski stated that it was not known if the equation x∕y+y∕z+z∕x=4 has solutions in positive integers. Bondarenko (Investigation of a class of Diophantine equations, UkraĂŻn. Mat. Zh. 52:6 (2000), 831–836) gave a negative answer to SierpiƄski’s remark by showing that the equation x∕y+y∕z+z∕x=4k2 does not have solutions in positive integers if 3∀k. However, Garaev (Diophantine equations of the third degree, Tr. Mat. Inst. Steklova 218 (1997), 99–108) had already proved that the equation x3+y3+z3=nxyz has no positive integer solutions if n=4k, n=8k−1, or n=22m+1(2k−1)+3, where m,k∈℀+, which Bondarenko’s result is a consequence of. In this paper, we shall partially extend Garaev’s result by showing that the equation x∕y+y∕z+m⋅(z∕x)=nm does not have solutions in positive integers if m is odd and 4∣n or 8∣n+1. Our method is different from Garaev’s method and has been successfully applied to several situations.

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