Abstract

A two-parameter density distribution has been obtained for He 6 using an oscillator shell model distribution with different oscillator length parameters a s and a p for the s and p-nucleons respectively. One relation between a s and a p is obtained by equating the calculated Coulomb energy difference between He 6 and the lowest T = 1 state of Li 6 with the empirical value while a second relation has been obtained using a method due to Überall which gives good agreement for the form factor of Li 6 and which assumes that the s-nucleon distribution is due to a recoiling α-particle. One then obtains a s = 1.79±0.04 fm, a p = 2.60±0.06 fm and 〉r 2〉 1 2 = 2.78±0.05 fm for the r.m.s. radius of the point nucleon distribution. Compared with Li 6 the extension of the s-nucleons is only slightly greater. However, 〈r 2〉 1 2 and the extension of the p-nucleons is significantly greater, consistent with the smaller binding energy of the p-nucleons in He 6. The effect of the Coulomb interaction in extending the p-nucleons in the T = 1 state of Li 6 beyond those in He 6 is shown to be negligible.

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