Abstract
AbstractThe molecular and crystal structure of TiMgCl6(CH3COOC2H5)4, obtained by reacting TiCl4 with a solution of MgCl2 in dry CH3COOC2H5, have been determined by x‐ray diffraction. The structure was solved by direct and Fourier methods and refined by least‐squares techniques to R = 0.052 for 2722 independent observed reflections. Unit‐cell dimensions are a = 17.122(7), b = 9.833(3), c = 9.646(3) Å, α = 111.10(7)°, β = 107.22(6)°, γ = 103.11(6)° with Z = 2 for P1. The titanium(IV) atom is octahedrally coordinated by six chlorine atoms (TiClt = 2.293(2) Å, TiClb = 2.480(2) Å) and magnesium by two chlorine atoms (MgClb = 2.528(2) Å) and the carbonyl oxygen atoms of the four CH3COOC2H5 residues (MgO = 2.038(5) Å). The octahedra share an edge by a double chlorine bridge between the magnesium and titanium atoms. Changes in the configurations and dimensions of the free acceptor and donor molecules on adduct formation are discussed. One of the ethylacetate residues shows positional disorder, eventually with Bonding through its ethereal oxygen.
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