Abstract
An unsymmetric bidentate ligand (3-methyl-2-pyridyl)diphenylphosphane (P(Mepy)Ph 2) is able to react with various tetranuclear transition metal clusters such as HRuCo 3(CO) 12, HRuRh 3(CO) 12 and Rh 4(CO) 12. The synthesis and crystal structures of HRuCo 3(CO) 10(P(Mepy)Ph 2) ( 1), HRuRh 3(CO) 10(P(Mepy)Ph 2) ( 2), RuRh 2(CO) 9(P(Mepy)Ph) ( 3) and Rh 6(CO) 14(P(Mepy)Ph 2) ( 4) are described. In 1, 2 and 4 the phosphane ligand replaces the carbonyls and acts as a bridging bidentate P–N group. The formation of 3 includes degradation of both the metal cluster core and the ligand itself. One of the P–C bonds in the ligand is cleaved and the ligand caps a metal triangle with a bridging phosphido group together with the nitrogen donor. The reaction between dinuclear Rh 2(CO) 4Cl 2 and P(Mepy)Ph 2 gives a binuclear Rh 2(μ-CO)Cl 2(P(Mepy)Ph 2) 2 ( 5) with bridging ligands in a head-to-tail arrangement. The crystal structure is also given.
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