Abstract

Rabbit brain contains a mixture of aldolase A (muscle type) and aldolase C (brain type), present largely as the hybrid forms A 3C, A 2C 2, and AC 3, with smaller amounts of the homopolymers A 4 and C 4. We have developed new procedures for the isolation of the A-C hybrid set and the aldolase C subunits and compared the structure of these subunits with those of aldolase A. The two isoenzymes differ significantly in amino acid composition, but each contains three methionine residues per subunit and yields four peptides on cleavage with cyanogen bromide. The three methionine residues appear to occupy similar positions in the polypeptide chains but the molecular weight of the aldolase C subunit is only 37,000, approximately 10% smaller than that of the subunit of aldolase A. The difference is attributable to two or more deletions, totaling 30–40 amino acid residues, in two of the four BrCN peptides. The deletions include two of the buried cysteine residues that are located in the center of the polypeptide chain in aldolase A; these residues in aldolase A are, therefore, not involved in the contacts between the subunits in the tetramer. Aldolase C also lacks several of the histidine residues that are located near the active-site lysine residue of aldolase A, thus excluding these residues from participation in the catalytic mechanism.

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