Abstract
The nucleus 11B has been studied over the excitation energy range from 8.5 MeV to 21.5 MeV with the 9Be( 3He, p) 11B / reaction at / E 3 He = 38 MeV . The analogs of the parent states in 11Be have been located at 12.56, 12.92, 14.40, 16.44, 17.69, 18.0, 19.15 and 21.27 MeV. A complementary measurement with the 9Be(α, d) 11B reaction at E α = 48 MeV demonstrates that the 16.44, 17.69, 18.0 and 19.15 MeV resonances have rather pure isospin T f = 3 2 . The 14.40 MeV state is a strongly isospin-mixed analog of the 5 2 +1.78 MeV state in 11Be. It is argued that spin S = 1 transfer is involved in the excitation of the 16.44 MeV state and its 3.887 MeV parent in 11Be in a two-step stripping process. The T f = 1 2 states and the lowest three T f = 3 2 states are compared with the predictions of DWBA utilizing shell-model form factors. It is concluded that the T f = 1 2 strength is more strongly fragmented than is implied by the calculations of Teeters and Kurath.
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