Abstract
Fluoroalkyl iodide RfI [RF=(CF2)nCl, n=2, 4, 6; CF3(CF2)n, n=1, 3; H(CF2)4] reacted with alkyne (CH≡CC4H9; CH≡CSiMe3; CH≡CC6H5) in the presence of catalytic amounts of tetrakis (triphenylphosphine) palladium (0) to give a mixture of E and Z-fluoroalkylated adduct. The reaction could not be catalyzed by dichloro-bis(triphenylphosphine)palladium (II) and fluoroalkyl complex of palladium (II). 2-Nitro-2-nitrosopropane partly suppressed the reaction. It is believed that the reaction proceeds through a free radical intermediate rather than fluoroalkyl complex of palladium (II).
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