Abstract
We present a proof of that SO 3( Q ) is not a simple group, using a quaternion cover for SO 3( Q ) . Moreover, we show that the set of square matrices in SO 3( Q ) is a normal subgroup. Using that result we give a proof of that the derived group of SO 3( Q ) is the kernel of homomorphism that maps SO 3( Q ) onto the countably infinite group ⊕ ω Z 2 .
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