Abstract
The standard molar enthalpy at 298.15 K was determined by solution-reaction calorimetry for the reaction: NiCl 2(cr) + 6NH 4Cl(cr) = [Ni(NH 3) 6]Cl 2(cr) + 6HCl(g). From the standard molar enthalpy of reaction, the standard molar enthalpy of formation of [Ni(NH 3) 6]Cl 2(cr) was derived. The derived value is in reasonably good agreement with a value given in the NBS tables of chemical thermodynamic properties, which was based on the analysis of the equilibria: NiCl 2(cr) + NH 3(g) = [Ni(NH 3)]Cl 2(cr), [Ni(NH 3)]Cl 2(cr) + NH 3(g) = [Ni(NH 3) 2]Cl 2(cr), and [Ni(NH 3) 2]Cl 2(cr) + 4NH 3(g) = [Ni(NH 3) 6)Cl 2(cr).
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